Integration by parts

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Integration by parts

Reminder Product rule is ;
derivative of
It follows then that

Which

Integration by parts Reminder Product rule is ; derivative of It follows
can be written

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Integration by parts

… we can perform more complex integration
of stuff like

Integration by parts … we can perform more complex integration of stuff
by letting v equal the least complex function

and

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Integration by parts

Example
Let v=x and

We need to know u and dv/dx

The
Formula:

and

Integration by parts Example Let v=x and We need to know u

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Integration by parts

Substitute in

Leads to

Integration by parts Substitute in Leads to

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Integration by parts

Find by integration by parts.
Use v = x and that gives

Integration by parts Find by integration by parts. Use v = x and that gives

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Why not “by substitution” ?

If u = e4x

then du/dx = 4 e4x

then

Why not “by substitution” ? If u = e4x then du/dx =
dx = du/(4 e4x)

We
get

GETTING NOWHERE

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Integration by parts of lnx

Example
lnx is difficult to integrate so consider the

Integration by parts of lnx Example lnx is difficult to integrate so
function as 1lnx and use by parts.
Let v = lnx and
So and u = x

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Integration by parts of lnx

Substitute in

Leads to

Integration by parts of lnx Substitute in Leads to

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The same method for integrating lnx can be used to integrate arcsinx.
So

The same method for integrating lnx can be used to integrate arcsinx.
v = arcsin x and
Therefore and u = x
Substitute in:

Integration by parts of arcsinx

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Integration by parts of arcsinx

Now use substitution to integrate
Let m = 1

Integration by parts of arcsinx Now use substitution to integrate Let m
– x2 so dm = -2xdx
So

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Integration by parts of arcsinx

So
Becomes

Integration by parts of arcsinx So Becomes

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This involves some algebraic manipulation since the second integral does not resolve

This involves some algebraic manipulation since the second integral does not resolve
into an easily integratable function.
Let v = ex and
Therefore and u = sinx
So:

Integration by parts of excosx

[1]

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Integrating by parts again for exsinx we get:
Rearranging:

Integration by parts of

Integrating by parts again for exsinx we get: Rearranging: Integration by parts of excosx [2]
excosx

[2]

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