Слайд 2Step 1: Example
we have shaft with:
Nominal diameter= 25 mm
Max limited dimension =25.015
mm
Min limited dimension =25.005 mm
It is necessary to:
1) calculate limited deviations
2) draw the tolerance zone of the dimension
Слайд 3Step 2: Calculation
We know two limited deviations:
Upper deviation: es=dmax- dn
Lower deviation: ei=dmin-dn
dn,
dmax & dmin are given:
dn=25 mm
dmax=25.015 mm
dmin=25.005 mm
So es= 25.015-25.000=0.015 mm=15μm (micrometers)
ei=25.005-25.000=0.005 mm=5 μm
Слайд 5Step 4: Drawing the boundaries of tolerance zone
Слайд 6Step 5: Drawing the zone & calculate the tolerance
Слайд 7Step 6: Tolerance zones for joint
For example we have two joint
parts (details):
shaft
bush
Слайд 8Step 7: Drawing the second zone
Слайд 9Step 8: Defining of the fit type
Some rules:
if hole zone upper than
shaft zone – it is clearance
if shaft zone upper than hole zone – it is interference
if zones are particularly or fully intersected – it is transition fit
Слайд 10Step 9: Calculate limited clearances (interferences)