How to draw the tolerance zone by nominal and limited dimensions (Seminar 1)

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Step 1: Example

we have shaft with:
Nominal diameter= 25 mm
Max limited dimension =25.015

Step 1: Example we have shaft with: Nominal diameter= 25 mm Max
mm
Min limited dimension =25.005 mm
It is necessary to:
1) calculate limited deviations
2) draw the tolerance zone of the dimension

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Step 2: Calculation

We know two limited deviations:
Upper deviation: es=dmax- dn
Lower deviation: ei=dmin-dn
dn,

Step 2: Calculation We know two limited deviations: Upper deviation: es=dmax- dn
dmax & dmin are given:
dn=25 mm
dmax=25.015 mm
dmin=25.005 mm
So es= 25.015-25.000=0.015 mm=15μm (micrometers)
ei=25.005-25.000=0.005 mm=5 μm

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Step 3: Drawing zero line

Step 3: Drawing zero line

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Step 4: Drawing the boundaries of tolerance zone

Step 4: Drawing the boundaries of tolerance zone

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Step 5: Drawing the zone & calculate the tolerance

Step 5: Drawing the zone & calculate the tolerance

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Step 6: Tolerance zones for joint

For example we have two joint

Step 6: Tolerance zones for joint For example we have two joint parts (details): shaft bush
parts (details):
shaft
bush

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Step 7: Drawing the second zone

Step 7: Drawing the second zone

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Step 8: Defining of the fit type

Some rules:
if hole zone upper than

Step 8: Defining of the fit type Some rules: if hole zone
shaft zone – it is clearance
if shaft zone upper than hole zone – it is interference
if zones are particularly or fully intersected – it is transition fit

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Step 9: Calculate limited clearances (interferences)

Step 9: Calculate limited clearances (interferences)
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